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3x^2=200^2
We move all terms to the left:
3x^2-(200^2)=0
We add all the numbers together, and all the variables
3x^2-40000=0
a = 3; b = 0; c = -40000;
Δ = b2-4ac
Δ = 02-4·3·(-40000)
Δ = 480000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{480000}=\sqrt{160000*3}=\sqrt{160000}*\sqrt{3}=400\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-400\sqrt{3}}{2*3}=\frac{0-400\sqrt{3}}{6} =-\frac{400\sqrt{3}}{6} =-\frac{200\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+400\sqrt{3}}{2*3}=\frac{0+400\sqrt{3}}{6} =\frac{400\sqrt{3}}{6} =\frac{200\sqrt{3}}{3} $
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